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1  General Category / Questions / Help with python subprocess.call on s3cmd sync on: December 03, 2009, 02:45:47 AM
I'm having a tough time using a subprocess.call to run s3cmd

here is where I'm stuck:

subprocess.call(["python", "s3cmd","sync", "C:\filepath", "S3://bucketpath"])

other lines have worked fine such as:

subprocess.call(["python", "s3cmd", "ls" "S3://bucktpath"])

Thanks for your help!!

I'm really stuck on this.
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